In sci.math message <MPG.firstname.lastname@example.org- september.org>, Sun, 9 Dec 2012 19:58:25, Wasell <Wasell@example.invalid> posted:
>On Sat, 8 Dec 2012 19:13:02 +0000, in article ><1tj7wWW+E5wQFwvR@invalid.uk.co.demon.merlyn.invalid>, Dr J R Stockton >wrote: > >> Can anyone (or more) please provide here the last ten decimal digits >(in >> order) of ((3^349)-1)/2, freshly and independently calculated and not >> copied from any other medium, and not using my LongCalc or VastCalc? > >$ perl -Mbigint -e 'print substr( ((3**349)-1)/2, -10 )' >7379284041
Some years ago, while reading a book that showed (roughly)
(3^349-1)/2 = three lines of digits = two lines of digits * two lines of digits
I noticed a missing digit near the beginning of the second "two lines", and reported it. I was evidently checking the expression against the multiplication. I have now noticed that your second 7 is, in the book, an 8 - 7389284041 - and wanted a cross-check before reporting the new fault. OTOH, before doing that, I should re-check ALL digits.
Mathematicians, or some of them, might recognise the expression.
See books.google.co.uk/books?isbn=0195130820, page 107.
7389284041 seems to be a Harshad number as well as one used by Indians.
-- (c) John Stockton, nr London, UK. Mail via homepage. Turnpike v6.05 MIME. Web <http://www.merlyn.demon.co.uk/> - FAQqish topics, acronyms and links; Astro stuff via astron-1.htm, gravity0.htm ; quotings.htm, pascal.htm, etc. No Encoding. Quotes before replies. Snip well. Write clearly. Don't Mail News.