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Re: Take Home Test
Posted:
Dec 17, 2012 10:28 AM


This might be a little late, but seems to me like this:
we have two equal quantities, so why not raise the same base to each of these quantities, and we have equal quantities again.
So,
e^(ln8x + ln4x) = e^ln33
now a number raised to the sum of two terms is equal to the product of the number raised to each term, so
e^ln8x times e^ln4x  e^ln33
But by the definition of ln, the left side and right side may be rewritten simply as
8x times 4x = 33
32x^2 = 33
x^2 = 33/32
x = +sqrt 33/32, a rather ugly result. That's how I would have done the problem.



