dpb
Posts:
6,841
Registered:
6/7/07
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Re: text file data into matrix format
Posted:
Dec 17, 2012 10:09 AM
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On 12/17/2012 1:07 AM, ali wrote:
> dpb <none@non.net> wrote in message <kaa90e$v58$1@speranza.aioe.org>...
...
>>
>> use a format string that matches...
>>
>> fmt=['x=%f, y=%f, z=%f'];
>> [x,y,z]=textread('yourfile.nam',fmt);
>>
...
> i have used the following codes
>
> b= importdata('new.txt');
> c= b(2:2:end,:);
> n=strrep(c,'=',' ')
> c = textscan(n, '%s %f, %s %f, %s %f')
>
>
> new.txt file contains the following amount of strings:
>
> x=-115, y=-143, z= 449
> x= -70, y= -29, z= 511
...
> x= 260, y= -83, z= 364
> x= 248, y= -92, z= 230
> but the textscan is not woriking. all i want to do is separating each x,
> y , z values in each columns so that i could make a graph.
>
> plz would you help.
...
Already did...sometimes the older tools are simpler/easier than the
newer-fangled ones...use textread() instead--
fmt=['x=%f, y=%f, z=%f'];
[x,y,z]=textread('new.txt',fmt);
If you only want the even-numbered rows, _now_ do the decimation--
x(1:2:end,:)=[]; % etc., for others
Or, of course, you can concatenate into a single array by
data=[x y z];
and then use data(1,:), etc., for x...
--
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