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grei
Posts:
128
Registered:
11/27/12


Re: Help with inequality
Posted:
Dec 21, 2012 9:30 AM


I take that when you said you "attempted was to solve it the same as though it were an equation", you mean that you multiplied both sides by x 1. The problem with that is that multiplying by a NEGATIVE number will reverse the direction of the inequality: 1< 3 but 1> 3. Here, we want to multiply by x 1 but because we don't know x, we don't know whether x 1 is positive or negative.
So one way to do this is to do it as two cases: Assume x 1> 0. Then multiplying both sides by x 1 does NOT change the inequality: 2>= (x 1)= x+ 1. Adding x to both sides and subtracting 2 from both sides gives x>= 1. But, of course, that is true for all positive numbers and this was assuming x 1> 0 which means x> 1.
Assume x 1< 0. Then multiplying by x 1 changes the direction of the inequality: 2<= (x 1)= x+ 1. Adding x to both sides and subtracting 2 from both sides now gives x<= 1. Of course, any x less than 1 also satisfies x 1< 0 so we have x<= 1.
Putting those together, the inequality is satisfied for all x< 1 and all x> 1.
Another way to do this is to solve the associated equation: 2/(x 1)= 1 is (for all x other than 1) the same as 2= x+ 1 or x= 1. The point of that is that we can change from "<" to ">", or vice versa, only where we have "=" or the function is not continuous. We have seen that we have equality where x= 1 and a fraction is not continuous where the denominator is 0, that is, at x= 1. Those two points Are the only places where the inequality can change. Check one point in each interval, x< 1, 1< x< 1, x> 1 to determine whether or not the inequality is satisfied by all points in that interval.



