On Dec 26, 12:28 am, Graham Cooper <grahamcoop...@gmail.com> wrote: > it fails because with Infinite Sets of Reals > You can alter the Number Order > To change the digit back!
THAT DOESN'T CHANGE anything! You can permute the list of reals ANY WAY YOU LIKE. That will give you A DIFFERENT anti-diagonal and thus a DIFFERENT new number but NEITHER THE NEW ANTI-DIAGONAL NOR THE OLD ONE will be on EITHER list! Obviously permuting the list does NOT change the answer to ANY question of the form "is x on this list?". It might change WHERE it is, if it's on there, but it does NOT change the answer to "yes it is" or "no it isn't".
> Its like putting a coin on a 2UP paddle > and giving it a one way opposing flip. > > Null Operation as you just flip it twice!
That's just ONE DIGIT, DUMBASS. THE ISSUE is about THE WHOLE new anti-diagonal. Changing the list does NOT change ANY digits of the OLD ORIGINAL anti-diagonal. It gives you a NEW list with a NEW anti- diagonal. Which is ALSO NOT ON the list. The issue in any case IS NOT EVEN WHETHER "the argument fails". The issue is whether the anti-diagonal IS OR IS NOT ON the list. And it is OBVIOUSLY NOT ON IT since it differs from EVERY real on the list.