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Topic: 1 variable Derrivative of 2 D function...but Error..why??
Replies: 1   Last Post: Dec 27, 2012 8:15 PM

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 Roger Stafford Posts: 5,929 Registered: 12/7/04
Re: 1 variable Derrivative of 2 D function...but Error..why??
Posted: Dec 27, 2012 8:15 PM

"Quynh Tram Nghuyen Thi" <lovelyeverything@yahoo.com.vn> wrote in message <kbhsun\$1k\$1@newscl01ah.mathworks.com>...
> Problem: Compute DERRIVATIVE of FUNCTION U(x,y) by 1 variable x , domain 2D:RxR
> I did:
> m-file diff2.m:
> function [du1]=diff2(Xi,Yi,Zi,X,Y,h)
> if nargin<6; h=1e-4;end;
> du1=(interp2(Xi,Yi,Zi,X+h)-interp2(Xi,Yi,Zi,X-h))/(2*h)
> .........
> diff2(u,v,z,u,v)
> ===>>>ERROR:Error using ==> interp2 at 140
> Wrong number of input arguments.

- - - - - - - - - -
The error message is telling you what is wrong. The interp2 function does not accept four arguments. Check its documentation. I believe what you need is:

du1=(interp2(Xi,Yi,Zi,X+h,Y)-interp2(Xi,Yi,Zi,X-h,Y))/(2*h);

As you have the code at present, you are not using diff2's Y input argument at all, and consequently interp2 has no way of telling what the precise y values are to be at the points where the partial derivatives with respect to x are to be taken. The values of y in Yi are in general offset from the correct locations. In any case interp2 does not know what to do here and is complaining.

I would also suggest that you beware of letting X+h and X-h fall out of range of Xi - otherwise you will receive NaNs from interp2.

Also I would suggest that your nomenclature for diff2 should probably be altered to show that differentiation is with respect to x and not y to prevent it from being misused in the future. Or perhaps you need to output both derivatives, one with respect to x and the other with respect to y:

[dx,dy] = diff2(....)

Roger Stafford

Date Subject Author
12/27/12 Quynh Tram Nghuyen Thi
12/27/12 Roger Stafford