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Topic:
CHANGING THE DIAGONAL!
Replies:
6
Last Post:
Dec 29, 2012 4:14 AM



Virgil
Posts:
8,833
Registered:
1/6/11


Re: CHANGING THE DIAGONAL!
Posted:
Dec 29, 2012 12:18 AM


In article <9533c4f1686c45be8ef8f7f4d3a9eab7@ui9g2000pbc.googlegroups.com>, Graham Cooper <grahamcooper7@gmail.com> wrote:
> On Dec 29, 11:37 am, Virgil <vir...@ligriv.com> wrote: > > In article > > <adde38fa1e6343a194f0908da37a4...@s6g2000pby.googlegroups.com>, > > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > > > > > > > > > > > > > > > > > +> > > >  0. 542.. > > >  0. 983.. > > >  0. 143.. > > >  0. 543.. > > >  ... > > > v > > > OK  THINK  don't back explain to me. > > > You run down the Diagonal 5 8 3 ... > > > IN YOUR MIND  > > > > > [1] > > > you change each digit ONE AT A TIME > > > 0.694... > > > but this process NEVER STOPS > > > > > [2] > > > so you NEVER CONSTRUCT A NEW DIGIT SEQUENCE! > > > > That is like saying that the function f+ N > N : x \_> x^2 > > never ends. > > > Right! but since it has no free variable input to apply it's safe to > extrapolate results toward infinity. > > > > > As soon as one has a completed rule by which values of the function are > > determined from its domain to its codomain, the function is defined. > > > > E.g., f:N > N : 2 > 2*x+1 > > is completed function > > > > Thus a rule or function for determining antidiagonal digits creates the > > entire antidiagonal list of digits in one step. > > > > dependent on the input. As a function of the input certainly, but one theat function is defined the process is essentially completed. > > In this case, you cannot ANTIDIAGONALISE an infinite set. > > Every digit you change is substitutable by another digit in another > permutation.
I have defined a function which does it automatically for any and every list of endless sequences of decimal digits, giving a resulting sequence not listed in that list. 



