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L'Hospitals rule
Posted:
Dec 30, 2012 8:13 AM


Please, if we have:
lim(x to 1)(x/(x1)1/lnx)) we get lim(x to 1) ((xlnxx+1)/(xlnxlnx)) now we take that x=1 and we apply LH rule:
how do we get now lim(x to 1) ((lnx+11)/(lnx +11/x)) after LH it should be f'(x)/g'(x)
so how did we get the reciprocical value? Many thanks



