On Sat, 29 Dec 2012 18:03:08 -0800, William Elliot <firstname.lastname@example.org> wrote:
>How long does an uncountable list with no duplicates, >of infinite binary sequences (IBS) have to be to force >the list to contain all the IBS's?
It's obvious that there is no length long enough to force this. A "list" of length c (the cardinality of the set of infinite binary sequences) need not contain all the sequences, and a list of length greater than c must contain duplicates (and still need not contain all the sequences).
This is because c is also the cardinality of the set of all binary sequences except (0,0,0,...).