quasi
Posts:
10,450
Registered:
7/15/05


Re: From Fermat little theorem to Fermat Last Theorem
Posted:
Dec 31, 2012 3:51 AM


John Jens wrote:
>I intentionally choose a < p ,there's no crime to choose >an a natural, a < p.
Right.
So let's assume you've proved that with the conditions
p prime, p > 2 a,b,c positive integers with a < p
the equation a^p + b^p = c^p cannot hold.
>If for a < p ,a,b,c, naturals , we can multiply the >inequality a^p + b^p != c^p with any rational number, >it will remain a inequality.
But that doesn't help you prove, subject to the conditions
p prime, p > 2 a,b,c positive rationals with a < p
that the equation a^p + b^p = c^p cannot hold.
You are making a rather blatant logical error.
Assume that there exist a,b,c,p with the conditions
p prime, p > 2 a,b,c positive rationals with a < p
such that a^p + b^p = c^p.
You can scale a,b,c up to get positive integers A,B,C such that A^p + B^p = C^p, but in scaling up, you can no longer guarantee A < p, so there's no contradiction.
quasi

