
Re: From Fermat little theorem to Fermat Last Theorem
Posted:
Jan 4, 2013 4:30 AM


Minor corrections:
If a^p != c^p  b^p is true for a , b , c ,naturals a < p , is true for a rational , a < p and b , c naturals because c^p b^p is natural.
We can divide a^p != c^p b^p with k^p , k rational k > 1 and note (a/k) = q ,
q^p != (c/k)^p  (b/k)^p with q rational q < p.
Let?s pick d positive integer , p < d , d?b < c and assume that d^p+b^p=c^p .
We can find k rational number such d/k < p and we have
(d/k)^p + (b/k)^p = (c/k)^p which is false of course because d/k < p

