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Re: equivalence of truth of Riemann hypothesis
Posted:
Jan 5, 2013 3:44 PM
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Op zaterdag 5 januari 2013 18:51:24 UTC+1 schreef David C. Ullrich het volgende: > On Sat, 5 Jan 2013 08:30:50 -0800 (PST), Jean Dupont > > <jeandupont115@gmail.com> wrote: > > > > >Op zaterdag 5 januari 2013 17:06:11 UTC+1 schreef David Bernier het volgende: > > >> On 01/05/2013 09:55 AM, Jean Dupont wrote: > > >> > > >> > In the book "Math goes to the movies" it is stated that the truth of the Riemann hypothesis is equivalent to the following statement: > > >> > > >> > $\exists C: \forall x \in \mathbb{N}_0: \left|\pi(x)-\operatorname{li}(x)\right| \leq C \sqrt{x} \log(x)$ > > >> > > >> > > > >> > > >> > Is this correct? > > >> > > >> > > > >> > > >> > thanks > > >> > > >> > jean > > >> > > >> > > >> > > >> The movie "A Beautiful Mind" about John Nash is now on Youtube: > > >> > > >> > > >> > > >> < http://www.youtube.com/watch?v=OOWT1371DRg > . > > >> > > >> > > >> > > >> I think John Nash in the movie or in reality tried to make > > >> > > >> head-way on the Riemann Hypothesis ... > > >> > > >> > > >> > > >> David Bernier > > >> > > >> > > >> > > >> P.S. I'm afraid I can't read Tex or Latex ... > > >just copy/paste the line > > > > > >exists C: \forall x \in \mathbb{N}_0: \left|\pi(x)-\operatorname{li}(x)\right| \leq C \sqrt{x} \log(x) > > > > > >in the box shown on the following web page and press render: > > >http://itools.subhashbose.com/educational-tools/latex-renderer-n-editor.html > > > > When in Rome... If someone's going to read the TeX you posted, the > > fact that it's TeX instead of text just makes it harder to read. You > > shouldn't expect people to take the trouble to render your posts > > just so they can have the privilege of answering your question! > > Instead just post text: > > > > |pi(x) - li(x)| <= C sqrt(x)/log(x) . > > > > Simple. Perfectly clear. > > > I think the part \exists C: \forall x \in \mathbb{N}_0: should not be omitted...
regards, jean
> >> > > >jean > > >> > > >> > > >> But, please see "error term" in Prime Number Theorem, here: > > >> > > >> > > >> > > >> primepages, 1901 von Koch result: > > >> > > >> > > >> > > >> < http://primes.utm.edu/notes/rh.html > > > >> > > >> > > >> > > >> I trust PrimePages. Also, Schoenfeld(1976) explicit bound: > > >> > > >> > > >> > > >> < http://en.wikipedia.org/wiki/Riemann_hypothesis > .
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