Wasell
Posts:
11
Registered:
9/29/10


Re: simplifying rational expressions
Posted:
Jan 16, 2013 3:33 AM


On Tue, 15 Jan 2013 23:59:53 0600, in article <uqfcf8dvhsqr7qjsdi09b8agcahbsr98ah@4ax.com>, stony wrote: > > Hi, > > Need a little help with this. We are simplifying the following, but > the solution is pretty lengthy and messy because of the enormous > number of factors. I was thinking that may be I am missing seeing a > pattern (some series or something). Is grunt work the only way to > solve this or is there a pattern that can simplify the whole process? > > My daughter was trying to solve this, but ended up with the mess and > then I got the same mess, but I thought there may be an easy way to > simplify this that I may be missing. > > > ((bc)/((ab)(ac))) + ((ca)/((bc)(ba))) + ((ab)/((ca)(cb))) + > (2/(ba))  (2/(ca)) > > > of course, I took all the factors in the denominator and then started > multiplying the numerator with the remaining factors to end up with a > mess. > > Your help is appreciated. > > s
Let x = ab, y = bc, z = ca.
Then the first three terms become (x^2 + y^2 + z^2)/(xyz).
Note that x+y = z, y+z = x, z+x = y.
I'm sure you can take it from there.
HTH /Wasell

