Thank you for the suggestion. I did try the equation after I solved it based on input from several other kind souls in here. That site did spit out the same answer. I will bookmark the site to check up on my answers to see whether I did them right. Thank you.
On Wed, 16 Jan 2013 10:18:00 -0200, "JJAthayde" <email@example.com> wrote:
> >"stony" <firstname.lastname@example.org> escreveu na mensagem >news:email@example.com... >> Hi, >> Need a little help with this. We are simplifying the following, but >> the solution is pretty lengthy and messy because of the enormous >> number of factors. I was thinking that may be I am missing seeing a >> pattern (some series or something). Is grunt work the only way to >> solve this or is there a pattern that can simplify the whole process? >> My daughter was trying to solve this, but ended up with the mess and >> then I got the same mess, but I thought there may be an easy way to >> simplify this that I may be missing. >> ((b-c)/((a-b)(a-c))) + ((c-a)/((b-c)(b-a))) + ((a-b)/((c-a)(c-b))) + >> (2/(b-a)) - (2/(c-a)) >> of course, I took all the factors in the denominator and then started >> multiplying the numerator with the remaining factors to end up with a >> mess. >> Your help is appreciated. >> s > >Hi Stony. > > With the help of Google I've found this site: > >http://www.quickmath.com/webMathematica3/quickmath/algebra/factor/basic.jsp > > As I've seen, it works OnLine, so you'll get a solution immediately. > I hope this will help you. > Bye, > >