
Re: simplifying rational expressions
Posted:
Jan 16, 2013 11:59 PM


Thank you for the suggestion. I did try the equation after I solved it based on input from several other kind souls in here. That site did spit out the same answer. I will bookmark the site to check up on my answers to see whether I did them right. Thank you.
s
On Wed, 16 Jan 2013 10:18:00 0200, "JJAthayde" <jjathayde@uol.com.br> wrote:
> >"stony" <x@x.com> escreveu na mensagem >news:uqfcf8dvhsqr7qjsdi09b8agcahbsr98ah@4ax.com... >> Hi, >> Need a little help with this. We are simplifying the following, but >> the solution is pretty lengthy and messy because of the enormous >> number of factors. I was thinking that may be I am missing seeing a >> pattern (some series or something). Is grunt work the only way to >> solve this or is there a pattern that can simplify the whole process? >> My daughter was trying to solve this, but ended up with the mess and >> then I got the same mess, but I thought there may be an easy way to >> simplify this that I may be missing. >> ((bc)/((ab)(ac))) + ((ca)/((bc)(ba))) + ((ab)/((ca)(cb))) + >> (2/(ba))  (2/(ca)) >> of course, I took all the factors in the denominator and then started >> multiplying the numerator with the remaining factors to end up with a >> mess. >> Your help is appreciated. >> s > >Hi Stony. > > With the help of Google I've found this site: > >http://www.quickmath.com/webMathematica3/quickmath/algebra/factor/basic.jsp > > As I've seen, it works OnLine, so you'll get a solution immediately. > I hope this will help you. > Bye, > >

