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Topic:
How to Define Derivative of a Vector Field in this Case ( Curve in R^3)?
Replies:
3
Last Post:
Jan 18, 2013 4:30 AM



trj
Posts:
95
From:
Korea
Registered:
2/23/12


Re: Derivative of a Vector Field
Posted:
Jan 18, 2013 4:30 AM


> On Thu, 17 Jan 2013, cku wrote: > > > Let C:I>R^3 be a smooth curve, and let Z(s) be a > vector field along > > the curve, parametrized by arclength. > > > > We define the derivative of a vector field Z along > the curve to be the quotient: > > > > Lim_ds>0 [Z(s+ds)Z(s)]/ds > > > > Now, I don't know how to make sense of the > difference in the numerator: > > Z(s + ds) and Z(s) are two vectors in R^3, as is > their difference.
That is incorrect. Z(s+ds) is an element of the tangent space at point C(s+ds), whereas Z(s) is an element of the tangent space at C(s). They cannot be added or subtracted, since they belong to different vector spaces.



