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Topic: Calendar formula for 2nd Wednesday of each successive month
Replies: 10   Last Post: Jan 27, 2013 12:21 AM

 Messages: [ Previous | Next ]
 plutonium.archimedes@gmail.com Posts: 18,572 Registered: 3/31/08
Re: Calendar formula for 2nd Wednesday of each successive month
Posted: Jan 25, 2013 12:05 AM

On Jan 24, 10:51 pm, Archimedes Plutonium
<plutonium.archime...@gmail.com> wrote:
> The last time I wrote about a calendar curiosity was
> when I asked how many calendar years do I need in order to not have to
> buy a new calendar. And the answer is 7, if we ignore leap years. The
> answer is 7 because I need only 7 calendars that start the january 1st
> with one of the seven days of the week. If I have those, I need not
>
> But now I have a new calendar question, sort of a reversal of the 7
> calendars. I am receiving social security checks every 2nd wednesday
> of the month.
> So the question is, what math formula can be written that tells me how
> many days in each month, starting January of 2013 for the next ten
> years, how many days in each month that I have to wait for the check.
>
> For example, January 2013, the first wednesday was 2nd and the second
> wednesday was the 9th which means I had to wait 9 days for Jan 2012 to

2013, not 2012

> receive the check. Now Feb 2012, the first wednesday is 6th and the

again 2013

> second wednesday is the 13th so I have to wait 13 days.
>
> So far I have this:
> 2013
> Jan wait 9
> Feb wait 13
> .
> .
> .
>
> So what is the formula that gives me those numbers without consulting
> a calendar? Here I would have to include leap years.
>
> And it is obvious that the numbers have a lower limit of 7 and a upper

lower limit is 8, not 7

> limit of 15, depending on what day is the first day of that month.
>
> What I am interested in is whether there is a internal pattern that
> can easily tell me if a month is going to have a early payday or
> whether it is near to 15 day wait.
>
> And I wonder if some years are going to have many 7 day paydays or
> many 15 day paydays, given that a
> probability of a 7 or 15 day month is about 1 per year since we have
> 12/7 = 1.7
>
> Anyone figure out a formula?
>
> And I would guess that there is a general formula for what day is the
> 1st of the month for the next ten years has been figured out and that
> this formula is part of the solution for the 2nd wednesday of each
> month.
>
> --
>
> Google's archives are top-heavy in hate-spew from search-engine-
> bombing. Only Drexel's Math Forum has done a excellent, simple and
> fair archiving of AP posts for the past 15 years as seen here:
>
> http://mathforum.org/kb/profile.jspa?userID=499986
>
> Archimedes Plutoniumhttp://www.iw.net/~a_plutonium
> whole entire Universe is just one big atom
> where dots of the electron-dot-cloud are galaxies