The Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Calendar formula for 2nd Wednesday of each successive month
Replies: 10   Last Post: Jan 27, 2013 12:21 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]

Posts: 18,572
Registered: 3/31/08
Re: Calendar formula for 2nd Wednesday of each successive month
Posted: Jan 25, 2013 12:12 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

On Jan 24, 10:51 pm, Archimedes Plutonium
<> wrote:
> The last time I wrote about a calendar curiosity was
> when I asked how many calendar years do I need in order to not have to
> buy a new calendar. And the answer is 7, if we ignore leap years. The
> answer is 7 because I need only 7 calendars that start the january 1st
> with one of the seven days of the week. If I have those, I need not
> buy any new calendar.
> But now I have a new calendar question, sort of a reversal of the 7
> calendars. I am receiving social security checks every 2nd wednesday
> of the month.
> So the question is, what math formula can be written that tells me how
> many days in each month, starting January of 2013 for the next ten
> years, how many days in each month that I have to wait for the check.
> For example, January 2013, the first wednesday was 2nd and the second
> wednesday was the 9th which means I had to wait 9 days for Jan 2012 to
> receive the check. Now Feb 2012, the first wednesday is 6th and the
> second wednesday is the 13th so I have to wait 13 days.
> So far I have this:
> 2013
> Jan wait 9
> Feb wait 13
> .
> .
> .
> So what is the formula that gives me those numbers without consulting
> a calendar? Here I would have to include leap years.
> And it is obvious that the numbers have a lower limit of 7 and a upper

8 lower limit

> limit of 15, depending on what day is the first day of that month.
> What I am interested in is whether there is a internal pattern that
> can easily tell me if a month is going to have a early payday or
> whether it is near to 15 day wait.
> And I wonder if some years are going to have many 7 day paydays or

8 day paydays not 7

> many 15 day paydays, given that a
> probability of a 7 or 15 day month is about 1 per year since we have

8 or 15

> 12/7 = 1.7

12/8 = 1.5

I corrected on the original with a (sic) sign
> Anyone figure out a formula?
> And I would guess that there is a general formula for what day is the
> 1st of the month for the next ten years has been figured out and that
> this formula is part of the solution for the 2nd wednesday of each
> month.
> --
> Google's archives are top-heavy in hate-spew from search-engine-
> bombing. Only Drexel's Math Forum has done a excellent, simple and
> fair archiving of AP posts for the past 15 years as seen here:
> Archimedes Plutonium
> whole entire Universe is just one big atom
> where dots of the electron-dot-cloud are galaxies

Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum at NCTM 1994-2018. All Rights Reserved.