On Jan 25, 5:00 pm, Wally W. <ww8...@aim.com> wrote: > On Thu, 24 Jan 2013 20:51:15 -0800 (PST), Archimedes Plutonium wrote: > > >The last time I wrote about a calendar curiosity was > >when I asked how many calendar years do I need in order to not have to > >buy a new calendar. And the answer is 7, if we ignore leap years. The > >answer is 7 because I need only 7 calendars that start the january 1st > >with one of the seven days of the week. If I have those, I need not > >buy any new calendar. > > >But now I have a new calendar question, sort of a reversal of the 7 > >calendars. I am receiving social security checks every 2nd wednesday > >of the month. > >So the question is, what math formula can be written that tells me how > >many days in each month, starting January of 2013 for the next ten > >years, how many days in each month that I have to wait for the check. > > The approach of finding and adapting a general formula seems overly > complicated for the one-off task. > > It will probably be easier to make a table of dates in a spreadsheet > and extract the desired dates. > > >For example, January 2013, the first wednesday was 2nd and the second > >wednesday was the 9th which means I had to wait 9 days for Jan 2012 to > >receive the check. Now Feb 2012, the first wednesday is 6th and the > >second wednesday is the 13th so I have to wait 13 days. > > >So far I have this: > >2013 > >Jan wait 9 > >Feb wait 13 > >. > >. > >. > > Your results are tabular. > > A spreadsheet can produce this output. > > > > > > > > > > >So what is the formula that gives me those numbers without consulting > >a calendar? Here I would have to include leap years. > > >And it is obvious that the numbers have a lower limit of 7 and a upper > >limit of 15, depending on what day is the first day of that month. > > >What I am interested in is whether there is a internal pattern that > >can easily tell me if a month is going to have a early payday or > >whether it is near to 15 day wait. > > >And I wonder if some years are going to have many 7 day paydays or > >many 15 day paydays, given that a > >probability of a 7 or 15 day month is about 1 per year since we have > >12/7 = 1.7 > > >Anyone figure out a formula? > > Maybe, but it would be complicated and would probably be evaluated in > a spreadsheet. > > Why bother with a formula when the spreadsheet can produce the result > you want without complexity. > > >And I would guess that there is a general formula for what day is the > >1st of the month for the next ten years > > That would be a list of 120 days. > > Such a list is easy to produce in a spreadsheet without needing to > find a general forumula. > > > > > > > > >has been figured out and that > >this formula is part of the solution for the 2nd wednesday of each > >month.
Most people would like to have some idea of "how it works", or the mechanism or the internal pattern, rather than be fed the facts of a spreadsheet.
One can easily get blueprints of a car engine, but what we really need to know is it works by explosions in cylinders, converted into forward motion.