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Topic:
Another Limit Problem
Replies:
4
Last Post:
Feb 11, 2013 11:48 AM




Re: Another Limit Problem
Posted:
Jan 29, 2013 12:06 PM


"A N Niel" <anniel@nym.alias.net.invalid> wrote in message news:290120130712519075%anniel@nym.alias.net.invalid... > In article <LbydnWRm6eYGV5rMnZ2dnUVZ_uKdnZ2d@earthlink.com>, Charles > Hottel <chottel@earthlink.net> wrote: > >> How can I find lim(x>0) tan 5x /sin 2 x ? >> >> I have tried manipulating this every way I can think of, but I still end >> up >> with a fraction that contains a denominator of zero. Thanks. >> >> > > Can you do lim(x>0) (sin x)/x ? > If so, think of how that may be relevant to your problem.
I know that lim(x>0) (sinx/x) = 1 and I was just about to reply that it does not help when I actually figured out a way that it does. Problem solved .Thanks.



