Search All of the Math Forum:

Views expressed in these public forums are not endorsed by NCTM or The Math Forum.

Notice: We are no longer accepting new posts, but the forums will continue to be readable.

Topic: Another Limit Problem
Replies: 4   Last Post: Feb 11, 2013 11:48 AM

 Messages: [ Previous | Next ]
 Charles Hottel Posts: 10 Registered: 9/5/11
Re: Another Limit Problem
Posted: Jan 29, 2013 12:06 PM

"A N Niel" <anniel@nym.alias.net.invalid> wrote in message
news:290120130712519075%anniel@nym.alias.net.invalid...
>

>> How can I find lim(x->0) tan 5x /sin 2 x ?
>>
>> I have tried manipulating this every way I can think of, but I still end
>> up
>> with a fraction that contains a denominator of zero. Thanks.
>>
>>

>
> Can you do lim(x->0) (sin x)/x ?
> If so, think of how that may be relevant to your problem.

I know that lim(x->0) (sinx/x) = 1 and I was just about to reply that it
does not help when I actually figured out a way that it does. Problem
solved .Thanks.

Date Subject Author
1/29/13 Charles Hottel
1/29/13 A N Niel
1/29/13 Charles Hottel
1/29/13 gnasher729
2/11/13 JEMebius