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Topic:
Another Limit Problem
Replies:
4
Last Post:
Feb 11, 2013 11:48 AM




Re: Another Limit Problem
Posted:
Jan 29, 2013 12:41 PM


On Jan 29, 1:12 pm, "Charles Hottel" <chot...@earthlink.net> wrote: > How can I find lim(x>0) tan 5x /sin 2 x ? > > I have tried manipulating this every way I can think of, but I still end up > with a fraction that contains a denominator of zero. Thanks.
l'Hospital.



