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Topic: Another Limit Problem
Replies: 4   Last Post: Feb 11, 2013 11:48 AM

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gnasher729

Posts: 417
Registered: 10/7/06
Re: Another Limit Problem
Posted: Jan 29, 2013 12:41 PM
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On Jan 29, 1:12 pm, "Charles Hottel" <chot...@earthlink.net> wrote:
> How can I find lim(x->0) tan 5x /sin 2 x  ?
>
> I have tried manipulating this every way I can think of, but I still end up
> with a fraction that contains a denominator of zero.  Thanks.


l'Hospital.



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