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Re: ZFC and God
Posted:
Jan 30, 2013 5:33 AM
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On 30 Jan., 09:47, Virgil <vir...@ligriv.com> wrote:
> In article
> <4a768b6d-0d71-4e89-bf77-6b70d6e5e...@d11g2000yqe.googlegroups.com>,
>
>
>
>
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> WM <mueck...@rz.fh-augsburg.de> wrote:
> > On 30 Jan., 02:17, Virgil <vir...@ligriv.com> wrote:
> > > In article
> > > <6a9608a5-ec9c-4e81-af59-ae4caa19b...@h2g2000yqa.googlegroups.com>,
>
> > > WM <mueck...@rz.fh-augsburg.de> wrote:
> > > > On 28 Jan., 22:52, "Jesse F. Hughes" <je...@phiwumbda.org> wrote:
>
> > > > > Now,
> > > > > if every real has a terminating decimal representation, then...
>
> > > > I did not say that every real has a terminating representation.
>
> > > But does every real accessible real have a decimal expansion, at least
> > > in theory?
>
> > No.
>
> > > Does every rational have a decimal expansion?
>
> > No. For instance 1/9 = 0.111... has no decimal expansion
>
> You just gave it one.
>
No. I know, it is very unfamiliar, but it is fact: "0.111..." is not a
decimal expansion. For instance, because decimal expansions by
definition have only one point. 0.111... is a finite definition of 1/9
like 1/9 is itself. It formulates a task, namely to find the n-th
digit of the decimal expansion. This task can be accomplished for
every n, but not for all.
Regards, WM
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