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Re: List manipulation question  2013
Posted:
Jan 30, 2013 10:05 PM


Lea,
You might try something like
Map[Position[list1,#]&,list2]
this will give you a list of how the two lists coincide. It means, for each element in list2, find its position in list1, and give me a list of the positions.
Chris
Lea Rebanks a écrit : > Dear All, > > I have the follow problem with the combination of a few lists. > I shall outline the problem or what I am trying to do. > I know that to solve this problem requires a number of processes, but I am > not sure how to setup the coding to achieve my desired result. > Please could someone show me the coding for this problem. > > The problem: > 1  I have a list1 created from 24+(15*n1) All n1 are integers > 1,2,3,4.....to a large number of integers. > 2  I want to divide the list1 by 24 and create another list2 with only the > integer results in list2. > Table[24 + 15*i, {i, 100}]/24 ... so that integer results in list2 > = { 144, 264, 384, 504, 624, 744, 864, 984, 1104 } > 3  I have another list3 created from 12+(3*n2) All n2 are integers > 1,2,3,4.....to a large number of integers. > 4  With list3 I want to find : > (i) The integer number of n2 that either equates 12+(3*n2) = 144 or > the next FIRST available number in list2 that meets this equality. > then also (ii)The integer number(s) of n2 that equates 12+(3*n2) = 24+(15*n1) after the first equal value for say 6 repetitions. > then also (iii)The integer number(s) of n1 that equates 12+(3*n2) = > 24+(15*n1) after the first equal value for say 6 repetitions. > > The above example is quite simple, but I am hoping to setup the coding to > work with other integer values instead of 3 & 15 which will present more of > a challenge. > > Any help or advice greatly appreciated. > Best regards, > Lea... > > > >



