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Re: Matheology § 203
Posted:
Feb 1, 2013 4:58 AM
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On Feb 1, 10:37 am, WM <mueck...@rz.fh-augsburg.de> wrote: > On 1 Feb., 09:35, William Hughes <wpihug...@gmail.com> wrote: > > > > > > > > > > > On Feb 1, 9:21 am, WM <mueck...@rz.fh-augsburg.de> wrote: > > > > On 31 Jan., 18:44, William Hughes <wpihug...@gmail.com> wrote: > > > > > On Jan 31, 4:34 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > > > > > > On 31 Jan., 16:15, William Hughes <wpihug...@gmail.com> wrote: > > > > > > > > Would you say that a line that is not in the list is in the list? > > > > > > > Nope. But you did. > > > > > > Yes, but for an actually infinite list. > > > > > What actually infinite list? > > > > > Specifically you said > > > > > A potentially infinite list, L, > > > > of potentially infinite 0/1 sequences > > > > can have the property that every > > > > (in the sense of "all from 1 to n") > > > > potentially infinite 0/1 sequence > > > > is a line of L? > > > > > No actually infinite lists here > > > > And what is your question please? Of course every line between line 1 > > > and line n is in the list. > > > Let a potentially infinite list, L, > > of potentially infinite 0/1 sequences > > have the property that every > > (in the sense of "all from 1 to n") > > potentially infinite 0/1 sequence > > is a line of L? > > A potentially infinite list does not contain every whatever in the > sense of all. Because a list that in contains all whatevers is actual > with respect to these whatevers. > > But of course the list contains every sequence that is a line between > 1 and n (including the limits) and therefore contains all these > sequences.
Yes, but every does not describe the list but the potentially infinite set of potentially infinite 0/1 sequences.
Please answer the question.
Let s be a potentially infinite 0/1 sequence.
Does this imply that there is a natural number m, such that s is the mth line of L
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