Drexel dragonThe Math ForumDonate to the Math Forum

Search All of the Math Forum:

Views expressed in these public forums are not endorsed by Drexel University or The Math Forum.

Math Forum » Discussions » sci.math.* » sci.math

Topic: Finite Rings
Replies: 28   Last Post: Feb 6, 2013 8:33 AM

Advanced Search

Back to Topic List Back to Topic List Jump to Tree View Jump to Tree View   Messages: [ Previous | Next ]

Posts: 11,309
Registered: 7/15/05
Re: Finite Rings
Posted: Feb 4, 2013 12:33 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

Butch Malahide wrote:
>quasi wrote:
>> William Elliot wrote:

>> >[In forum "Ask an Algebraist", user "Anu" asks:]
>> >> If R is a finite commutative ring without multiplicative
>> >> identity and if every element is a zero divisor, then does
>> >> there exist a nonzero element which annihilates all elements
>> >> of the ring?

>> >No - the trivial ring.
>> >So add the premise that R has a nonzero element.

>> Even with that correction, the answer is still "no".
>> Consider the commutative ring R consisting of the following
>> seven distinct elements:
>>    0, x, y, z, x+y, y+z, z+x

>Does this mean that the additive group of R is a group of order 7?

>> Besides the usual laws required for R to be a commutative
>> ring (without identity), we also require the following
>> relations:
>>    r^2 = r for all r in R
>>    r+r = 0 for all r in R

>If r is nonzero, then r is an element of order 2 in the additive
>group? What about Lagrange's theorem?

Oops. I missed the element x+y+z.

But then x+y+z is an annihilator -- which destroys my attempted

>>    xy = yz = zx = 0
>> Note that the above relations imply
>>    (x+y)z = (y+z)x = (z+x)y = 0
>> so every element of R is a zerodivisor.
>> However, since all elements of R are idempotent, it follows
>> that no nonzero element of R annihilates all elements of R.


Point your RSS reader here for a feed of the latest messages in this topic.

[Privacy Policy] [Terms of Use]

© The Math Forum 1994-2015. All Rights Reserved.