
Re: This is False. 0/0 {x  x ~e x} e {x  x ~e x} A single Principle to Resolve Several Paradoxes
Posted:
Feb 4, 2013 4:14 PM


On Feb 4, 10:26 pm, CharlieBoo <shymath...@gmail.com> wrote: > If e(x,y) were a predicate then not(e(x,x)) would be a predicate but > because of diagonalization it is not. > > What I believe about Prolog consists only of its being a database and > query language similar to predicate calculus (aka FOL.) > > Then I take it that: > > if [ not [ e rs rs ]] [ e rs rs ] Line 1 X => rs > if [ e rs rs ] [ not [ e rs rs ]] Line 2 X => rs > [ not [ e rs rs ]] = = [ e rs rs ] Def = = , if > ~P = = P [ e rs rs ] > => P > > Then some axiom about ~P = = P.
Yes, something like
thm( X ) < if( not(X), P ) ^ if( not(X), not(P) )
but this is forward chaining so it needs to be depth limited or PROLOG will just recurse the first if(L,R) rule it finds!
> > In Combinatory Logic: > > M x => N x x Def M > M M => N M M x => M > > There is no M M = = N M M because it is executed (no Turing Machine > can halt both yes and no because it stops as soon as it halts either > cf Rosser 1936.) M M and N M M occur at different points in time! > The system simply changes its mind as it goes along learning using AI > techniques. The circle is amicable. > > In CBL: > > M # P(x) / Q(a,b) means program/wff M enumerates/represents set P and > is written in programming language/logic Q meaning Q(x,y) iff program/ > wff M outputs at some point/is provable on input y. Then Q(M,x) = = > P(x) (all x). Abbreviated M#P/Q means P=Q(M). > > P(x) / Q(a,b) means (exists M) M # P(x) / Q(a,b) There is a program/ > wff that enumerates/represents set P. > > Let SE(x,y) iff set x contains element y. > > Then the Russell Paradox is: > > ~SE(x,x) / SE(a,b) There is a set of all sets that do not contain > themselves. > M # ~SE(x,x) / SE(a,b) Let M be the set of all sets that do not > contain themselves. > SE(M,x) = = ~SE(x,x) Def # / > SE(M,M) = = ~SE(M,M) x => M > P = = ~P SE(M,M) => P > > This is encapsulated in axiom (lower level theorem)  ~P/P where  E > means expression E is not true and P/Q abbreviates P(x)/Q(a,b) or > P(x,x)/Q(a,b) if P is 2place. Then if P/Q then P differs from Q and > we prove truth, provability and unrefutability distinct (Godel, > Rosser, Smullyan)  see 18 Word Proof in FOM July 2010. > > CB >
Sure you can syntactically eliminate strings like "~e(X,X)"
in NFU Set Theory.
I'm working on using
NOT( PROVABLE( T ) ) <> DERIVE( NOT(T) )
EXISTS( SET( S ) ) <> PROVABLE ( EXIST (SET (S) ) ) AXIOM OF SET SPECIFICATION
Herc
 www.BLoCKPROLOG.com

