fom
Posts:
1,038
Registered:
12/4/12
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Re: Matheology § 203
Posted:
Feb 5, 2013 3:13 AM
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On 2/5/2013 1:57 AM, Virgil wrote: > In article <NrmdnTGwGq_kBo3MnZ2dnUVZ_tudnZ2d@giganews.com>, > fom <fomJUNK@nyms.net> wrote: > >> On 2/4/2013 6:00 PM, fom wrote: >>> On 2/4/2013 5:14 PM, Virgil wrote: >>>> In article <tbCdnURtDtB9so3MnZ2dnUVZ_sWdnZ2d@giganews.com>, >>>> fom <fomJUNK@nyms.net> wrote: >>>> >>>>> >>>>> From the beginning (I showed up when Zuhair was asking questions) >>>>> I have not understood terminology. A CIBT is the Cantor space. >>>>> It is a topological construct and the C refers to topological >>>>> completeness. >>>> >>>> In my disputes with WM, a "CIBT" or "COMPLETE INFINITE BINARY TREE" >>>> is a countably infinite set of nodes, with a unique root node and such >>>> that every node has two child nodes, a "left child" and a "right child", >>>> and every node but the root node has one parent node for which it is >>>> either a left child or a right child. >>>> >>>> One can model it with its nodes being positive naturals: >>>> >>>> 1 >>>> / \ >>>> / \ >>>> 2 3 >>>> / \ / \ >>>> 4 5 6 7 >>>> / \ / \ / \ / \ >>>> >>>> So that the left child of any node n is 2*n and its right child is >>>> 2*n+1, and the parent of any node n except 1 is floor(n/2). >>>>> >>> >>> >>> Yes. I gathered that and it is nice to see it >>> framed classically. >>> >>> Would not infinite binary tree suffice? What >>> confused me initially was the inclusion of the >>> modifier "complete". >> >> I suppose not. In discrete presentations, the >> length of a tree is probably described relative >> to the length at the terminal node of the longest >> branch (usually with a +1 somewhere). Consequently, >> complete here means that every node has a branch >> for every symbol of the alphabet -- in this case 2. > > A path in a binary tree is any maximal chain of parent-child linked > nodes in a binary tree, and such a tree is complete if all paths are of > equal length. In an infinite binary tree that means each path is a > countably infinite set of nodes. >
Thanks
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