On 7 Feb., 08:39, Virgil <vir...@ligriv.com> wrote: > In article > <bbdf841d-effe-48c8-b938-0825f9e82...@fv9g2000vbb.googlegroups.com>, > > WM <mueck...@rz.fh-augsburg.de> wrote: > > Matheology § 222 Back to the roots > > > Consider a Cantor-list with entries a_n and anti-diagonal d: > > > For every n: (a_n1, a_n2, ..., a_nn) =/= (d_1, d_2, ..., d_n). > > For every n: (a_n1, a_n2, ..., a_nn) is terminating. > > For every n: (d_1, d_2, ..., d_n) is terminating. > > Even if there is last a_n and a last a_nn, n, the d_m's can still go > on without end.. > > > > > For all n: (a_n1, a_n2, ..., a_nn) =/= (d_1, d_2, ..., d_n). > > For all n: (a_n1, a_n2, ..., a_nn) is terminating. > > For all n: (d_1, d_2, ..., d_n) is *not* terminating. > > While (d_1, d_2, ..., d_n) may be terminating, > d_1, d_2, ..., d_n, ... need *not* ever terminate.
The diagonal argument includes merely all (d_1, d_2, ..., d_n).
