On 7 Feb., 19:46, William Hughes <wpihug...@gmail.com> wrote: > Gosh, you are really running away > from the fact that induction can > show d is not in the list.
Induction can show that *your* d does not exist. Therefore it cannot be in any list.
But if you neverthelss assume that your d exists, then among *your* finite terms a_n = (a_n1, ..., a_nn) can (and must) also exist infinite finite terms. Something that probably will easily be deparadoxided by the subuncountability of supercountable subcollections.
