On 7 Feb., 20:12, William Hughes <wpihug...@gmail.com> wrote: > On Feb 7, 8:06 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > > > On 7 Feb., 19:46, William Hughes <wpihug...@gmail.com> wrote: > > > > Gosh, you are really running away > > > from the fact that induction can > > > show d is not in the list. > > > Induction can show that *your* d does not exist. > > My d? You are the one who defined d to be > the antidiagonal of the list.
The antidiagonal of a list is not always in the list, but the diagonal of the list
1 11 111 ...
is with certainty in this very list - since it is nothing else but a potentially infinite sequence of 1' and not longer than the lines.
> You also > show by induction that the antidiagonal of > a list is not in the list.
No, that depends on the list.
The antidiagonal of the list
0.0 0.1 0.11 0.111 ... when changing 0 to 1 is in the list, when changing 0 to 2 it is not.
