dpb
Posts:
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Registered:
6/7/07


Re: Making a square matrix from two vector
Posted:
Feb 8, 2013 1:40 PM


On 2/8/2013 9:42 AM, Jerry wrote: > "a" is a vector (size 1by11) and "b" is also a vector (size 11by1), > in that the first number of these two vectors is the same so "a1"="b1". > I would like to create a square matrix (size of this matrix is > 11by11), from these two vectors in that "a" is the first row of this > matrix and "b" is the first column of this matrix. In fact, I am going > to use this function [F = (a + b) + (a * b)] to fill out the rest of > this matrix. So, the shape of matrix would be in this way: > > a1=b1 a2 a3 a4 a5 a6 a7 a8 a9 a10 a11 > b2 b2a2 b2a3 b2a4 b2a5 ... b3 b3a2 > b4 ... > > b9 > b10 > b11 ................................. b11a11 >
>> a=1:4; b=[1:2:8]'; >> [X,Y]=meshgrid(a,b); >> F = @(x,y) ((x+y) + (x.*y)); >> c=zeros(length(a)); c(:,1)= b; c(1,:)=a; >> c(2:end,2:end)=arrayfun(F,X(2:end,2:end),Y(2:end,2:end)); >> c c = 1 2 3 4 3 11 15 19 5 17 23 29 7 23 31 39 >>
I _think_ this is same order as you wanted; reverse X,Y here if the inner portion of c is the transpose of what you're after...


