In article <9f0b86ba-50b9-4692-8858-6b0788c7ed0c@x15g2000vbj.googlegroups.com>, WM <mueckenh@rz.fh-augsburg.de> wrote:
> We show that the potentially infinite diagonal is in the list by > proving that every o_nn is in the list. And every o that is in the > list, is in some line of the list. And everything that is in some line > of the list is in one line of the list. > > Anything wrong with this conclusion?
Every member of a sequence can be in a list of members of sequences without the sequence being in the list of sequences.
Consider the list L1 = 1, L2 = 2, L3 = 3 Which does not contain D = 123 even though every member of D is in one of L1 or L2 or L3
WM's claim is no more true than claiming that the union of a family of sets must be one of the family being unioned.
The union of all FISONs (finite initial segments of naturals) is not a FISON.
Given a list of all FISONs, the union of them is not a FISON. Thus give a list of successively FISON-long strings, a string as long as their union cannot be one of them. --
