In article <9f87d9d9-0974-4098-80c1-9ed239f0b541@ia3g2000vbb.googlegroups.com>, WM <mueckenh@rz.fh-augsburg.de> wrote:
> On 12 Feb., 13:34, William Hughes <wpihug...@gmail.com> wrote: > > On Feb 12, 10:17 am, WM <mueck...@rz.fh-augsburg.de> wrote: > > > 1 > 12 > 123 > ... > > > > That means d is something that never is so complete that more than > > > FISs of it exist. Therefore only FISs of it can be somewhere. > > > > Thus we have: There is one line of the list that contains > > every FIS of d. > > Every FIS of d is (in) a line of the list.
But, by construction, no line of the list is a FIS of d.
> Every line of the list is a FIS of d and contains all smaller FISs of > d.
If the list starts .0, .10, .110, and d starts .111..., as it would have to, then NONE of these lines of the list is a FIS of d.
SO WM is, as usual, TOTALLY WRONG AGAIN!
> There is no line of the list that contains all FISs of d (because > there are not all).
If there are not all FISs of d then there is no d.
But that can only happen in weird unreal places like Wolkenmuekenheim. > > > > > and > > > > the potentially infinite sequence d is not equal to the > > potentially infinite sequence given by a line of the list. > > > > This is still a contradiction. > > Why? A line of the list cannot give d (since there is no completed d).
There is outside of the dank dark dismal depths of Wolkenmuekenheim. > > There is no contradiction.
There are lots of them in the dank dark dismal depths of Wolkenmuekenheim. --
