On Feb 14, 8:38 pm, quasi <qu...@null.set> wrote: >Paul wrote: >>The papers states that the second moment of X~U(a,b) is: >> >> E(X^2) = ( b^3 - a^3 ) / 3(b-a) >> >>My own integration of x^2 from a to b yields (b^3-a^3)/3. > > >Can anyone point out where Hauptmanns's extra normalization > >factor 1/(b-a) comes from? > > The probability mass function is 1/(b-a).
Doh! I don?t do this sort of thing nearly enough, and I?m trying to consume more advanced material.