On Feb 16, 1:04 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > On 15 Feb., 23:58, William Hughes <wpihug...@gmail.com> wrote:
> > So WMs statements are > > > there is a line l such that d and l > > are coFIS > > Of course, for every n there is a line 1, 2, 3, ..., n that is coFIS > to the diagonal 1, 2, 3, ..., n.
Nope. a line is either coFIS to d or it is not.
It makes sense to say
For every n there is a line, l(n) such that the nth FIS of d. But this does not make l(n) coFIS to d.
And there is not more than every n.
> > there is no line l such that d and l > > are coFIS
> That would only be true if there was an n larger than every n
?? The statement is yours. Are you now withdrawing it.
