On Feb 16, 3:32 pm, William Hughes <wpihug...@gmail.com> wrote: > On Feb 16, 1:04 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > > > On 15 Feb., 23:58, William Hughes <wpihug...@gmail.com> wrote: > > > So WMs statements are > > > > there is a line l such that d and l > > > are coFIS > > > Of course, for every n there is a line 1, 2, 3, ..., n that is coFIS > .> to the diagonal 1, 2, 3, ..., n. > > Nope. a line is either coFIS to d or it is not. > > It makes sense to say > > For every n there is a line, l(n) such that
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> the nth FIS of l(n) is the nth FIS of d . > But this does not make l(n) coFIS to d. > > > > And there is not more than every n. > > > > there is no line l such that d and l > > > are coFIS > > That would only be true if there was an n larger than every n > > ?? The statement is yours. Are you now withdrawing it.