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Tom D
Posts:
7
Registered:
8/4/10


Re: Low precision exponentiation
Posted:
Feb 18, 2013 6:00 AM


Use N[(25/10)^125,30] to get the highprecision answer.
= 5.52714787526044456024726519219*10^49
The input has to be specified to at least the desired precision. Mathematica treats 2.5 as a machineprecision number.
Hope that helps, Tom
On Sun, 17 Feb 2013 09:08:38 +0000 (UTC), Blaise F Egan <blaise@blaisefegan.me.uk> wrote:
>I am trying to evaluate 2.5^125 to high precision. > >R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision. > >I am inexperienced at Mathematica. Am I doing something silly? > >Blaise



