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Re: Low precision exponentiation
Posted:
Feb 18, 2013 6:00 AM


In Mathematica 2.5 is a machine precision number and applying N to it does nothing. You could use SetPrecision but a better way is to use exact input:
N[(5/2)^125,30] 5.52714787526044456024726519219*10^49
Andrzej Kozlowski
On 17 Feb 2013, at 10:08, Blaise F Egan <blaise@blaisefegan.me.uk> wrote:
> I am trying to evaluate 2.5^125 to high precision. > > R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision. > > I am inexperienced at Mathematica. Am I doing something silly? > > Blaise >



