You are not doing anything "silly"; you're just being caught by two common traps for Mathematica beginners.
First, by default Mathematica treats 2.5 as a machine-precision number; no matter what you do with it as is, you won't get any more than machine-precision as result. You need to specify you mean exactly that number, to the desired precision, e.g.:
Second, no matter what the precision of a number, by default Mathematica only _displays_ 6 significant digits. To get more digits, use NumberForm (or depending on the format you want, perhaps ScientificForm, EngineeringForm, or AccountingForm), with second argument the number of digits to display.
Actually, in such an example you probably want to be more careful, since the calculation may lose precision. In fact:
Precision[N[2.5`30^125, 30]] 27.9031
You've lost 2 to 3 digits of precision. So just increase the precision in the calculation:
Precision[N[2.5`40^125, 40]] 37.9031
Which means that when you display 30 digits of N[2.5`40^125, 40] with NumberForm, all 30 digits will be correct.
On Feb 17, 2013, at 4:08 AM, Blaise F Egan <firstname.lastname@example.org> wrote:
> I am trying to evaluate 2.5^125 to high precision. > > R gives 5.527147875260445183346e+49 as the answer but Mathematica with N[2.5^125,30] gives 5.52715*10^49 and says that is to machine precision. > > I am inexperienced at Mathematica. Am I doing something silly?
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