On Feb 20, 5:29 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > On 20 Feb., 13:31, William Hughes <wpihug...@gmail.com> wrote: > > > On Feb 20, 12:37 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > > > > On 20 Feb., 11:30, William Hughes <wpihug...@gmail.com> wrote: > > <snip> > > > > A statement you can make is that there > > > > is no line of the list with the property > > > > that it is coFIS to d. > > > > (you do not need every line or every FIS to "actually > > > > exist" to make this statement) > > > > You need all FISs of d to make this statement. > > > No, for each line of L you only need some > > of the FISs. For every line you need every > > not all. > > Then you have a statement for finitely many lines and none for > infinitely many lines. > > > > > > > > > > > > > <snip> > > > > > Let z be a potentially infinite sequence such that > > > > for some natural number m, the mth FIS of > > > > z contains a zero. > > > > > Are z and x coFIS? > > > > No. > > > Is the following statement true > > > For every natural number n we have > > > the (n+1)st FIS of the nth line > > of L contains a 0. > > Of course.
Is the statement
For every natural number n we have the nth line of L and x are not coFIS
