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Re: An equivalent of MK-Foundation-Choice
Posted:
Feb 22, 2013 9:48 PM
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On Feb 22, 3:38 pm, Zuhair <zaljo...@gmail.com> wrote:
> On Feb 22, 10:23 pm, Charlie-Boo <shymath...@gmail.com> wrote:
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> > On Feb 22, 5:14 am, Zuhair <zaljo...@gmail.com> wrote:
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> > > On Feb 21, 11:10 pm, Charlie-Boo <shymath...@gmail.com> wrote:
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> > > > On Feb 20, 6:01 pm, Zuhair <zaljo...@gmail.com> wrote:
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> > > > > This is just a cute result.
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> > > > > The following theory is equal to MK-Foundation-Choice
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> > > > > Language: FOL(=,e)
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> > > > > Define: Set(x) iff Ey. x e y
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> > > > > Axioms: ID axioms+
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> > > > > 1.Extensionality: (Az. z e x <-> z e y) -> x=y
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> > > > > 2. Construction: if phi is a formula in which x is not free,
> > > > > then (ExAy.y e x<->Set(y)&phi) is an axiom
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> > > > > 3. Pairing: (Ay. y e x -> y=a or y=b) -> Set(x)
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> > > > > 4. Size limitation
> > > > > Set(x) <-> Ey. y is set sized & Azex(Emey(z<<m))
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> > > > > where y is set sized iff Es. Set(s) & y =< s
> > > > > and z<<m iff z =<m & AneTC(z).n =<m
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> > > > > TC(z) stands for 'transitive closure of z' defined in the usual manner
> > > > > as the minimal transitive class having z as subclass of; transitive of
> > > > > course defined as a class having all its members as subsets of it.
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> > > > > y =< s iff Exist f. f:y-->s & f is injective.
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> > > > > /
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> > > > > Of course this theory PROVES the consistency of ZFC.
> > > > > Proofs had all been worked up in detail. It is an enjoying experience
> > > > > to try figure them out.
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> > > > Why don't you supply your proof of ZFC consistency in detail then? If
> > > > that is too much, then why not give it for 2 potentially conflicting
> > > > axioms in detail, as I suggested recently?
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> > > > Why waste space with unsubstantiated claims of grandeur?
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> > > > C-B
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> > > > > Zuhair
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> > > Of course I'll supply them in DETAIL. There is no grandeur, nothing
> > > like that. That matter has been PROVED. I just wanted some to enjoy
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> > What has been proved?
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> > > figuring it out before I send the whole written proof.
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> > What are you waiting for?
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> > I'll bet you $25 to your $1 that you don't supply a proof, payable via
> > PayPal. Are we on? Only condition is you have to answer every
> > question - no obfuscation, please.
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> > It'd be well worth $25 if you have a proof of ZF consistency and I was
> > one of the first to be able to give it. Has it been proven before?
> > It seems people say "if ZF were consistent". Who has tried? Does
> > Gödel's 2nd Theorem mean you'll do math that ZF can't?
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> > C-B
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> > > Zuhair
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> There is some confusion here. What I'm claiming is that IF we hold
> that theory presented here to be consistent then MK minus foundation
> minus choice would be consistent, and thus ZFC would be proved
> consistent. I'm speaking about a relative consistency proof here.
>
> Zuhair
"Of course this theory PROVES the consistency of ZFC. Proofs had all
been worked up in detail." This seems to be saying clearly that you
have developed a proof that ZFC is consistent.
Now you're saying if one system is consistent then another is? Sure,
if system X plus a few more axioms is consistent, then by definition
system X is also consistent. Knowing that connection between 2
systems might signify nothing, depending on the relationship between
the two systems.
C-B
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