On Feb 26, 12:47 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > We both agree
There does not exist an m such that the mth line of L is coFIS with the diagonal (here we interpret "There does not exist" to mean "we cannot find").
So we agree any such m must be an unfindable natural number.
I am not interested in arguments about whether an unfindable number exists.
[I still do not understand why WM rejects the obvious proof by contradiction
Suppose that P is a predicate such that for every natural number m, P(m) is true.
Assume a natural number, x, such that P(x) is false exists. call it k Then P(k) is both true and false. Contradiction, Thus the original assumption is false and no natural number, x, such that P(x) is false exists) ]
<snip>
> Every natural number is findable.
Which, according to WM does not mean that you can prove every natural number is findable.
