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Topic: Alternative solution for NAN
Replies: 11   Last Post: Feb 27, 2013 5:44 PM

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Torsten

Posts: 1,439
Registered: 11/8/10
Re: Alternative solution for NAN
Posted: Feb 27, 2013 5:47 AM
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"Carl S." wrote in message <kgkmon$aeo$1@newscl01ah.mathworks.com>...
> "Torsten" wrote in message <kgklbh$6ph$1@newscl01ah.mathworks.com>...
> > "Carl S." wrote in message <kgki2g$rie$1@newscl01ah.mathworks.com>...
> > > The following code gives NAN (Not a Number) values
> > > [U,D]=eig(N);
> > >
> > > To solve this problem, I wrote that
> > > while(det(N) == 0)
> > > N=(1e-10.*randi(1,size(N)))*eye(size(N));
> > > end
> > >
> > > But, the loop does not stop

> >
> > Your matrix N within the loop always has determinant (1e-10)^(size(N))
> > which may become very small if N is large.
> >
> > :( Are there any alternative solution instead of this loop to solve the NAN problem ?
> >
> > Depends on the original matrix N.
> >
> > Best wishes
> > Torsten.

>
> Dear Torsten,
> The matrix N has standard deviation values of grayscale images. So, it changes for each image. How to solve the NAN problem in this case ?


Did you check whether the matrix N already contains NaN values ?

Best wishes
Torsten.



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