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Re: An unknown Greek matrix
Posted:
Mar 2, 2013 3:43 AM


A = {{5, 0}, {0, 10}}; B = {{6, 3}, {1, 12}}; L = {1, 1}; Lambda = {Subscript[lambda, 1], Subscript[lambda, 2]};
Solve[Lambda.B == Lambda.A + L, Lambda]
{{Subscript[lambda, 1] > 1, Subscript[lambda, 2] > 2}}
Bob Hanlon
On Thu, Feb 28, 2013 at 9:26 PM, <marshfeldman@gmail.com> wrote: > Forgive me if this is obvious, but I'm a Mathematica newbie and have given up trying to figure this out any other way. > > I have the following defined matrices: > > A = {{5, 0}, {0, 10}} > B = {{6, 3}, {1, 12}} > > and a row vector: > > L = {{1, 1}}. > > I don't know how to use Greek here, so I'll use "Lambda" as the name of a row vector whose name is really the Greek letter lambda capitalized and "lambda" for as the name of the elements of Lambda subscripted, with the elements really being lowercase versions of the Greek letter lambda and subscripts indicated by appending _n, where n is the subscript (e.g. lambda_1 is lowercase lambda subscripted with 1). In other words, > > Lambda = {{lambda_1, lambda_2}}. > > Now given the following equation, solve for Lambda: > > Lambda B = Lambda A + L. > > Also, display the elements of Lambda as > > lambda_1 = 1 > lambda_2 = 2. > > Can one do this in Mathematica? How? >



