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Topic: Theory of errors: center of gravity
Replies: 7   Last Post: Mar 14, 2013 2:40 PM

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 David Jones Posts: 80 Registered: 2/9/12
Re: Theory of errors: center of gravity
Posted: Mar 7, 2013 4:29 PM

"Allamarein" wrote in message

Let's suppose we have two point masses:

m1 = 4 kg, m2 = 3.5

Their associated standard deviation are:

dm1 = 0.5 kg, dm2 = 0.2 kg

Their distance from the origin of the reference frame are (1D problem):

x1 = 0.7 m, x2 = 0.8 m

Their associated standard deviation is:

dx1 = 0.01 m, dx2 = 0.01 m

I have to find the center of gravity (CoG) of this system and its
uncertainty. The nominal value can be found with the well-known relation:

X = (m1*x1 + m2*x2)/(m1+m2) = 0.7467 m

In order to find the associated uncertainty, I used the relationship for
non-linear combinations (cf.
http://en.wikipedia.org/wiki/Propagation_of_uncertainty), evaluating the
four partial derivatives of the previous relationship.

Hence dX = 0.0079 m

In my opinion is not an intuitive result: in fact the uncertainty of the
center of gravity is less than the uncertainty on the position of each mass.
Are you able to justify this result?

Regards

=================================================================================

Are you?

Suggest you look at the result in the case that there is no uncertainty in
the masses.

Date Subject Author
3/7/13 Red Star
3/7/13 David Jones
3/7/13 Paul
3/10/13 Red Star
3/10/13 Paul
3/10/13 Paul
3/14/13 Red Star
3/7/13 Steve Oakley