GS Chandy
Posts:
4,348
From:
Hyderabad, Mumbai/Bangalore, India
Registered:
9/29/05
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Re: Please help me with the following question
Posted:
Mar 7, 2013 9:00 PM
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Robert Hansen posted Mar 8, 2013 12:39 AM (GSC's remarks interspersed):
>
> lol, I really didn't think my answer would have
> stumped you.
>
lol, your answer stumped me - and I had a short time ago posted a question expressing my bewilderment.
>
>Here is a simpler version. Split the
> group into two groups of 6, keep the heavier group,
> split that into two groups of 3 keep the heavier
> group, weight (any) 2 coins from the remain group of
> 3, if they weigh the same then the other coin is the
> hevier one, if not then the heavier one is the
> heavier one.
>
> It is a binary search.
>
> Bob Hansen
>
Your 'simpler version' is just plain and simply wrong. Read the puzzle more carefully.
GSC
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