Kaba
Posts:
289
Registered:
5/23/11


Re: F^I isomorphic to finite(F^I)
Posted:
Mar 8, 2013 11:29 AM


8.3.2013 18:27, Kaba wrote: > U = {sum_{i in I} alpha_i b_i : alpha_i in finite(F^I)},
That should of course read
U = {sum_{i in I} alpha_i b_i : alpha in finite(F^I)}.
 http://kaba.hilvi.org

