On 8 Mrz., 17:15, William Hughes <wpihug...@gmail.com> wrote: > On Mar 8, 4:55 pm, WM <mueck...@rz.fh-augsburg.de> wrote: > > > On 8 Mrz., 15:45, William Hughes <wpihug...@gmail.com> wrote: > > > > WM: There does not exist > > > (in the sense of not findable) > > > a natural number m such that > > > the mth line of L is coFIS with > > > d > > > > So let's talk about d the way you > > > talk about d. > > You find it reasonable to say > > a line of L is not coFIS with d
L = d Every line L_k of L is identical with FIS d_1, ..., d_k of d. d is nothing but it sFIS
> > The question is > > Do you agree with the statement > > g is not coFIS with d.
Let us remember: Two potentially infinite sequences x and y are said to be coFIS iff for every natural number n, the nth FIS of x is equal to the nth FIS of y.
This is obviously the case for that line L_max which is identical with the maximal FIS of d:
1, 2, 3, ..., max = 1, 2, 3, ..., max On the the left-hand side you see the line L_max or g, on the right- hand side you see d, i.e., everything that in potential infinity can be assumed to exist of lines and d.