On 10 Mrz., 01:37, Virgil <vir...@ligriv.com> wrote:
> And where is WM's proof that some mapping from the set of all binary > sequences to the set of all paths of a CIBT is a linear mapping? > WM several times claimed it but cannot seem to prove it.
You will not understand it. Or you will deny the definition. Or you will simply make trouble as your well-known favourite occupation. Therefore I said EOD with respect to this topic.
If ax + by exists, then f(ax + by) = af(x) + bf(y). If ax + by does not exists, then f(ax + by) and af(x) + bf(y) do not exist. This is my definition of isomorphism. Accept it or not, understand it or not.