In article <firstname.lastname@example.org>, WM <email@example.com> wrote:
> On 10 Mrz., 17:40, William Hughes <wpihug...@gmail.com> wrote: > > > There is no findable line that is > > coFIS to (d) > > (d) is *not* an actual infinite sequence but only a description in > letters.
But d is the name of an actually infinite sequence, everywhere outside Wolkenmuekenheim. > > > g is a findable line. > > > > Do you agree with the statement > > > > g is not coFIS to (d) > > Of course. The number m = max is not findable or fixable.
Or existable. >
WM has claimed that a mapping from the set of all infinite binary sequences to the set of paths of a CIBT is a linear mapping. In order to show that such a mapping is a linear mapping, WM must first show that the set of all binary sequences is a vector space and that the set of paths of a CIBT is also a vector space, which he has not done and apparently cannot do, and then show that his mapping satisfies f(ax + by) = af(x) + bf(y), where a and b are arbitrary members of the field of scalars and x and y are binary sequences and f(x) and f(y) are paths in a CIBT.
By the way, WM, what are ax and by and ax+by when x and y are binary sequences?
If a = 1/3 and x is binary sequence, what is ax ? and if f(x) is a path in a CIBT, what is af(x)?
Until these and a few other issues are settled, WM will still have failed to justify his claim of a LINEAR mapping from the set (but not yet proved to be vector space) of binary sequences to the set (but not yet proved to be vector space) of paths ln a CIBT. --