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Re: How to take mean in 3rd dimension of matrix within a loop
Posted:
Mar 15, 2013 3:08 PM


"Max " <nizabat@gmail.com> wrote in message news:khvah3$7ov$1@newscl01ah.mathworks.com... > Dears, > I want to take average of long data array in 3rd dimension, but I am not > getting the wanted result. Lets say I have A = rand(8,8,10); Now > averaging (mean) over let say each 2 values in 3rd dimension, it should > give me size 8x8x5. > I did this, but doesn't work > A1 = []; > for m = 1: 2: 10 > A1 = [A1; mean(A(:,:,m:m+1),3)]; > end > > Any help in this regard would highly appreciated. Thanks
B = (A(:, :, 1:2:end) + A(:, :, 2:2:end)) / 2;
or if you want to avoid the ENDs for some reason:
nPages = size(A, 3); B = (A(:, :, 1:2:nPages) + A(:, :, 2:2:nPages)) / 2;
Note that if A is 4orhigher dimensional this will do something you may not expect. See example 2 on this page:
http://www.mathworks.com/help/matlab/ref/size.html
 Steve Lord slord@mathworks.com To contact Technical Support use the Contact Us link on http://www.mathworks.com



